11 KiB
11 KiB
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# Square root:
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# Square:
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s = 'hello'
# Print out 'e' using indexing
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s ='hello'
# Reverse the string using slicing
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s ='hello'
# Print out the 'o'
# Method 1:
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# Method 2:
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# Method 1:
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# Method 2:
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list3 = [1,2,[3,4,'hello']]
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list4 = [5,3,4,6,1]
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d = {'simple_key':'hello'}
# Grab 'hello'
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d = {'k1':{'k2':'hello'}}
# Grab 'hello'
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# Getting a little tricker
d = {'k1':[{'nest_key':['this is deep',['hello']]}]}
#Grab hello
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# This will be hard and annoying!
d = {'k1':[1,2,{'k2':['this is tricky',{'tough':[1,2,['hello']]}]}]}In [ ]:
list5 = [1,2,2,33,4,4,11,22,3,3,2]
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# Answer before running cell
2 > 3In [ ]:
# Answer before running cell
3 <= 2In [ ]:
# Answer before running cell
3 == 2.0In [ ]:
# Answer before running cell
3.0 == 3In [ ]:
# Answer before running cell
4**0.5 != 2In [ ]:
# two nested lists
l_one = [1,2,[3,4]]
l_two = [1,2,{'k1':4}]
# True or False?
l_one[2][0] >= l_two[2]['k1']